Integrand size = 29, antiderivative size = 254 \[ \int \frac {\cos ^4(c+d x) \cot ^2(c+d x)}{(a+b \sin (c+d x))^2} \, dx=-\frac {x}{2 b^2}-\frac {3 \left (a^2-b^2\right ) x}{b^4}-\frac {2 \left (a^2-b^2\right )^{3/2} \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a b^4 d}+\frac {4 \left (2 a^6-3 a^4 b^2+b^6\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a^3 b^4 \sqrt {a^2-b^2} d}+\frac {2 b \text {arctanh}(\cos (c+d x))}{a^3 d}-\frac {2 a \cos (c+d x)}{b^3 d}-\frac {\cot (c+d x)}{a^2 d}+\frac {\cos (c+d x) \sin (c+d x)}{2 b^2 d}-\frac {\left (a^2-b^2\right )^2 \cos (c+d x)}{a^2 b^3 d (a+b \sin (c+d x))} \]
[Out]
Time = 0.27 (sec) , antiderivative size = 254, normalized size of antiderivative = 1.00, number of steps used = 16, number of rules used = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.379, Rules used = {2976, 3855, 3852, 8, 2718, 2715, 2743, 12, 2739, 632, 210} \[ \int \frac {\cos ^4(c+d x) \cot ^2(c+d x)}{(a+b \sin (c+d x))^2} \, dx=\frac {2 b \text {arctanh}(\cos (c+d x))}{a^3 d}-\frac {2 \left (a^2-b^2\right )^{3/2} \arctan \left (\frac {a \tan \left (\frac {1}{2} (c+d x)\right )+b}{\sqrt {a^2-b^2}}\right )}{a b^4 d}-\frac {3 x \left (a^2-b^2\right )}{b^4}-\frac {\left (a^2-b^2\right )^2 \cos (c+d x)}{a^2 b^3 d (a+b \sin (c+d x))}-\frac {\cot (c+d x)}{a^2 d}+\frac {4 \left (2 a^6-3 a^4 b^2+b^6\right ) \arctan \left (\frac {a \tan \left (\frac {1}{2} (c+d x)\right )+b}{\sqrt {a^2-b^2}}\right )}{a^3 b^4 d \sqrt {a^2-b^2}}-\frac {2 a \cos (c+d x)}{b^3 d}+\frac {\sin (c+d x) \cos (c+d x)}{2 b^2 d}-\frac {x}{2 b^2} \]
[In]
[Out]
Rule 8
Rule 12
Rule 210
Rule 632
Rule 2715
Rule 2718
Rule 2739
Rule 2743
Rule 2976
Rule 3852
Rule 3855
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {3 \left (-a^2+b^2\right )}{b^4}-\frac {2 b \csc (c+d x)}{a^3}+\frac {\csc ^2(c+d x)}{a^2}+\frac {2 a \sin (c+d x)}{b^3}-\frac {\sin ^2(c+d x)}{b^2}-\frac {\left (a^2-b^2\right )^3}{a^2 b^4 (a+b \sin (c+d x))^2}+\frac {2 \left (2 a^6-3 a^4 b^2+b^6\right )}{a^3 b^4 (a+b \sin (c+d x))}\right ) \, dx \\ & = -\frac {3 \left (a^2-b^2\right ) x}{b^4}+\frac {\int \csc ^2(c+d x) \, dx}{a^2}+\frac {(2 a) \int \sin (c+d x) \, dx}{b^3}-\frac {\int \sin ^2(c+d x) \, dx}{b^2}-\frac {(2 b) \int \csc (c+d x) \, dx}{a^3}-\frac {\left (a^2-b^2\right )^3 \int \frac {1}{(a+b \sin (c+d x))^2} \, dx}{a^2 b^4}+\frac {\left (2 \left (2 a^6-3 a^4 b^2+b^6\right )\right ) \int \frac {1}{a+b \sin (c+d x)} \, dx}{a^3 b^4} \\ & = -\frac {3 \left (a^2-b^2\right ) x}{b^4}+\frac {2 b \text {arctanh}(\cos (c+d x))}{a^3 d}-\frac {2 a \cos (c+d x)}{b^3 d}+\frac {\cos (c+d x) \sin (c+d x)}{2 b^2 d}-\frac {\left (a^2-b^2\right )^2 \cos (c+d x)}{a^2 b^3 d (a+b \sin (c+d x))}-\frac {\int 1 \, dx}{2 b^2}-\frac {\left (a^2-b^2\right )^2 \int \frac {a}{a+b \sin (c+d x)} \, dx}{a^2 b^4}-\frac {\text {Subst}(\int 1 \, dx,x,\cot (c+d x))}{a^2 d}+\frac {\left (4 \left (2 a^6-3 a^4 b^2+b^6\right )\right ) \text {Subst}\left (\int \frac {1}{a+2 b x+a x^2} \, dx,x,\tan \left (\frac {1}{2} (c+d x)\right )\right )}{a^3 b^4 d} \\ & = -\frac {x}{2 b^2}-\frac {3 \left (a^2-b^2\right ) x}{b^4}+\frac {2 b \text {arctanh}(\cos (c+d x))}{a^3 d}-\frac {2 a \cos (c+d x)}{b^3 d}-\frac {\cot (c+d x)}{a^2 d}+\frac {\cos (c+d x) \sin (c+d x)}{2 b^2 d}-\frac {\left (a^2-b^2\right )^2 \cos (c+d x)}{a^2 b^3 d (a+b \sin (c+d x))}-\frac {\left (a^2-b^2\right )^2 \int \frac {1}{a+b \sin (c+d x)} \, dx}{a b^4}-\frac {\left (8 \left (2 a^6-3 a^4 b^2+b^6\right )\right ) \text {Subst}\left (\int \frac {1}{-4 \left (a^2-b^2\right )-x^2} \, dx,x,2 b+2 a \tan \left (\frac {1}{2} (c+d x)\right )\right )}{a^3 b^4 d} \\ & = -\frac {x}{2 b^2}-\frac {3 \left (a^2-b^2\right ) x}{b^4}+\frac {4 \left (2 a^6-3 a^4 b^2+b^6\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a^3 b^4 \sqrt {a^2-b^2} d}+\frac {2 b \text {arctanh}(\cos (c+d x))}{a^3 d}-\frac {2 a \cos (c+d x)}{b^3 d}-\frac {\cot (c+d x)}{a^2 d}+\frac {\cos (c+d x) \sin (c+d x)}{2 b^2 d}-\frac {\left (a^2-b^2\right )^2 \cos (c+d x)}{a^2 b^3 d (a+b \sin (c+d x))}-\frac {\left (2 \left (a^2-b^2\right )^2\right ) \text {Subst}\left (\int \frac {1}{a+2 b x+a x^2} \, dx,x,\tan \left (\frac {1}{2} (c+d x)\right )\right )}{a b^4 d} \\ & = -\frac {x}{2 b^2}-\frac {3 \left (a^2-b^2\right ) x}{b^4}+\frac {4 \left (2 a^6-3 a^4 b^2+b^6\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a^3 b^4 \sqrt {a^2-b^2} d}+\frac {2 b \text {arctanh}(\cos (c+d x))}{a^3 d}-\frac {2 a \cos (c+d x)}{b^3 d}-\frac {\cot (c+d x)}{a^2 d}+\frac {\cos (c+d x) \sin (c+d x)}{2 b^2 d}-\frac {\left (a^2-b^2\right )^2 \cos (c+d x)}{a^2 b^3 d (a+b \sin (c+d x))}+\frac {\left (4 \left (a^2-b^2\right )^2\right ) \text {Subst}\left (\int \frac {1}{-4 \left (a^2-b^2\right )-x^2} \, dx,x,2 b+2 a \tan \left (\frac {1}{2} (c+d x)\right )\right )}{a b^4 d} \\ & = -\frac {x}{2 b^2}-\frac {3 \left (a^2-b^2\right ) x}{b^4}-\frac {2 \left (a^2-b^2\right )^{3/2} \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a b^4 d}+\frac {4 \left (2 a^6-3 a^4 b^2+b^6\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a^3 b^4 \sqrt {a^2-b^2} d}+\frac {2 b \text {arctanh}(\cos (c+d x))}{a^3 d}-\frac {2 a \cos (c+d x)}{b^3 d}-\frac {\cot (c+d x)}{a^2 d}+\frac {\cos (c+d x) \sin (c+d x)}{2 b^2 d}-\frac {\left (a^2-b^2\right )^2 \cos (c+d x)}{a^2 b^3 d (a+b \sin (c+d x))} \\ \end{align*}
Time = 2.22 (sec) , antiderivative size = 215, normalized size of antiderivative = 0.85 \[ \int \frac {\cos ^4(c+d x) \cot ^2(c+d x)}{(a+b \sin (c+d x))^2} \, dx=\frac {\frac {2 \left (-6 a^2+5 b^2\right ) (c+d x)}{b^4}+\frac {8 \left (a^2-b^2\right )^{3/2} \left (3 a^2+2 b^2\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a^3 b^4}-\frac {8 a \cos (c+d x)}{b^3}-\frac {2 \cot \left (\frac {1}{2} (c+d x)\right )}{a^2}+\frac {8 b \log \left (\cos \left (\frac {1}{2} (c+d x)\right )\right )}{a^3}-\frac {8 b \log \left (\sin \left (\frac {1}{2} (c+d x)\right )\right )}{a^3}-\frac {4 \left (a^2-b^2\right )^2 \cos (c+d x)}{a^2 b^3 (a+b \sin (c+d x))}+\frac {\sin (2 (c+d x))}{b^2}+\frac {2 \tan \left (\frac {1}{2} (c+d x)\right )}{a^2}}{4 d} \]
[In]
[Out]
Time = 1.37 (sec) , antiderivative size = 304, normalized size of antiderivative = 1.20
method | result | size |
derivativedivides | \(\frac {\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{2 a^{2}}+\frac {\frac {2 \left (-b^{2} \left (a^{4}-2 a^{2} b^{2}+b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )-b a \left (a^{4}-2 a^{2} b^{2}+b^{4}\right )\right )}{\left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a +2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+a}+\frac {2 \left (3 a^{6}-4 a^{4} b^{2}-a^{2} b^{4}+2 b^{6}\right ) \arctan \left (\frac {2 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+2 b}{2 \sqrt {a^{2}-b^{2}}}\right )}{\sqrt {a^{2}-b^{2}}}}{a^{3} b^{4}}-\frac {2 \left (\frac {\frac {\left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) b^{2}}{2}+2 \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a b -\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right ) b^{2}}{2}+2 a b}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{2}}+\frac {\left (6 a^{2}-5 b^{2}\right ) \arctan \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2}\right )}{b^{4}}-\frac {1}{2 a^{2} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}-\frac {2 b \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a^{3}}}{d}\) | \(304\) |
default | \(\frac {\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{2 a^{2}}+\frac {\frac {2 \left (-b^{2} \left (a^{4}-2 a^{2} b^{2}+b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )-b a \left (a^{4}-2 a^{2} b^{2}+b^{4}\right )\right )}{\left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a +2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+a}+\frac {2 \left (3 a^{6}-4 a^{4} b^{2}-a^{2} b^{4}+2 b^{6}\right ) \arctan \left (\frac {2 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+2 b}{2 \sqrt {a^{2}-b^{2}}}\right )}{\sqrt {a^{2}-b^{2}}}}{a^{3} b^{4}}-\frac {2 \left (\frac {\frac {\left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) b^{2}}{2}+2 \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a b -\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right ) b^{2}}{2}+2 a b}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{2}}+\frac {\left (6 a^{2}-5 b^{2}\right ) \arctan \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2}\right )}{b^{4}}-\frac {1}{2 a^{2} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}-\frac {2 b \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a^{3}}}{d}\) | \(304\) |
risch | \(-\frac {3 x \,a^{2}}{b^{4}}+\frac {5 x}{2 b^{2}}-\frac {i {\mathrm e}^{2 i \left (d x +c \right )}}{8 b^{2} d}-\frac {a \,{\mathrm e}^{i \left (d x +c \right )}}{b^{3} d}-\frac {a \,{\mathrm e}^{-i \left (d x +c \right )}}{b^{3} d}+\frac {i {\mathrm e}^{-2 i \left (d x +c \right )}}{8 b^{2} d}+\frac {2 i \left (i a^{4} b \,{\mathrm e}^{2 i \left (d x +c \right )}-2 i a^{2} b^{3} {\mathrm e}^{2 i \left (d x +c \right )}+2 i b^{5} {\mathrm e}^{2 i \left (d x +c \right )}+a^{5} {\mathrm e}^{3 i \left (d x +c \right )}-2 a^{3} b^{2} {\mathrm e}^{3 i \left (d x +c \right )}+a \,b^{4} {\mathrm e}^{3 i \left (d x +c \right )}-i a^{4} b +2 i a^{2} b^{3}-2 i b^{5}-{\mathrm e}^{i \left (d x +c \right )} a^{5}+2 a^{3} b^{2} {\mathrm e}^{i \left (d x +c \right )}-3 a \,b^{4} {\mathrm e}^{i \left (d x +c \right )}\right )}{a^{2} d \,b^{4} \left (2 a \,{\mathrm e}^{3 i \left (d x +c \right )}-i b \,{\mathrm e}^{4 i \left (d x +c \right )}-2 a \,{\mathrm e}^{i \left (d x +c \right )}+2 i b \,{\mathrm e}^{2 i \left (d x +c \right )}-i b \right )}-\frac {3 \sqrt {-a^{2}+b^{2}}\, a \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i a -\sqrt {-a^{2}+b^{2}}}{b}\right )}{d \,b^{4}}+\frac {\sqrt {-a^{2}+b^{2}}\, \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i a -\sqrt {-a^{2}+b^{2}}}{b}\right )}{d \,b^{2} a}+\frac {2 \sqrt {-a^{2}+b^{2}}\, \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i a -\sqrt {-a^{2}+b^{2}}}{b}\right )}{d \,a^{3}}+\frac {3 \sqrt {-a^{2}+b^{2}}\, a \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i a +\sqrt {-a^{2}+b^{2}}}{b}\right )}{d \,b^{4}}-\frac {\sqrt {-a^{2}+b^{2}}\, \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i a +\sqrt {-a^{2}+b^{2}}}{b}\right )}{d \,b^{2} a}-\frac {2 \sqrt {-a^{2}+b^{2}}\, \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i a +\sqrt {-a^{2}+b^{2}}}{b}\right )}{d \,a^{3}}-\frac {2 b \ln \left ({\mathrm e}^{i \left (d x +c \right )}-1\right )}{a^{3} d}+\frac {2 b \ln \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )}{a^{3} d}\) | \(675\) |
[In]
[Out]
none
Time = 0.70 (sec) , antiderivative size = 901, normalized size of antiderivative = 3.55 \[ \int \frac {\cos ^4(c+d x) \cot ^2(c+d x)}{(a+b \sin (c+d x))^2} \, dx=\left [-\frac {3 \, a^{4} b^{2} \cos \left (d x + c\right )^{3} + {\left (6 \, a^{5} b - 5 \, a^{3} b^{3}\right )} d x \cos \left (d x + c\right )^{2} - {\left (6 \, a^{5} b - 5 \, a^{3} b^{3}\right )} d x - {\left (3 \, a^{4} b - a^{2} b^{3} - 2 \, b^{5} - {\left (3 \, a^{4} b - a^{2} b^{3} - 2 \, b^{5}\right )} \cos \left (d x + c\right )^{2} + {\left (3 \, a^{5} - a^{3} b^{2} - 2 \, a b^{4}\right )} \sin \left (d x + c\right )\right )} \sqrt {-a^{2} + b^{2}} \log \left (\frac {{\left (2 \, a^{2} - b^{2}\right )} \cos \left (d x + c\right )^{2} - 2 \, a b \sin \left (d x + c\right ) - a^{2} - b^{2} + 2 \, {\left (a \cos \left (d x + c\right ) \sin \left (d x + c\right ) + b \cos \left (d x + c\right )\right )} \sqrt {-a^{2} + b^{2}}}{b^{2} \cos \left (d x + c\right )^{2} - 2 \, a b \sin \left (d x + c\right ) - a^{2} - b^{2}}\right ) - {\left (3 \, a^{4} b^{2} + 2 \, a^{2} b^{4}\right )} \cos \left (d x + c\right ) - 2 \, {\left (b^{6} \cos \left (d x + c\right )^{2} - a b^{5} \sin \left (d x + c\right ) - b^{6}\right )} \log \left (\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right ) + 2 \, {\left (b^{6} \cos \left (d x + c\right )^{2} - a b^{5} \sin \left (d x + c\right ) - b^{6}\right )} \log \left (-\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right ) - {\left (a^{3} b^{3} \cos \left (d x + c\right )^{3} + {\left (6 \, a^{6} - 5 \, a^{4} b^{2}\right )} d x + {\left (6 \, a^{5} b - 5 \, a^{3} b^{3} + 4 \, a b^{5}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{2 \, {\left (a^{3} b^{5} d \cos \left (d x + c\right )^{2} - a^{4} b^{4} d \sin \left (d x + c\right ) - a^{3} b^{5} d\right )}}, -\frac {3 \, a^{4} b^{2} \cos \left (d x + c\right )^{3} + {\left (6 \, a^{5} b - 5 \, a^{3} b^{3}\right )} d x \cos \left (d x + c\right )^{2} - {\left (6 \, a^{5} b - 5 \, a^{3} b^{3}\right )} d x - 2 \, {\left (3 \, a^{4} b - a^{2} b^{3} - 2 \, b^{5} - {\left (3 \, a^{4} b - a^{2} b^{3} - 2 \, b^{5}\right )} \cos \left (d x + c\right )^{2} + {\left (3 \, a^{5} - a^{3} b^{2} - 2 \, a b^{4}\right )} \sin \left (d x + c\right )\right )} \sqrt {a^{2} - b^{2}} \arctan \left (-\frac {a \sin \left (d x + c\right ) + b}{\sqrt {a^{2} - b^{2}} \cos \left (d x + c\right )}\right ) - {\left (3 \, a^{4} b^{2} + 2 \, a^{2} b^{4}\right )} \cos \left (d x + c\right ) - 2 \, {\left (b^{6} \cos \left (d x + c\right )^{2} - a b^{5} \sin \left (d x + c\right ) - b^{6}\right )} \log \left (\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right ) + 2 \, {\left (b^{6} \cos \left (d x + c\right )^{2} - a b^{5} \sin \left (d x + c\right ) - b^{6}\right )} \log \left (-\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right ) - {\left (a^{3} b^{3} \cos \left (d x + c\right )^{3} + {\left (6 \, a^{6} - 5 \, a^{4} b^{2}\right )} d x + {\left (6 \, a^{5} b - 5 \, a^{3} b^{3} + 4 \, a b^{5}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{2 \, {\left (a^{3} b^{5} d \cos \left (d x + c\right )^{2} - a^{4} b^{4} d \sin \left (d x + c\right ) - a^{3} b^{5} d\right )}}\right ] \]
[In]
[Out]
\[ \int \frac {\cos ^4(c+d x) \cot ^2(c+d x)}{(a+b \sin (c+d x))^2} \, dx=\int \frac {\cos ^{6}{\left (c + d x \right )} \csc ^{2}{\left (c + d x \right )}}{\left (a + b \sin {\left (c + d x \right )}\right )^{2}}\, dx \]
[In]
[Out]
Exception generated. \[ \int \frac {\cos ^4(c+d x) \cot ^2(c+d x)}{(a+b \sin (c+d x))^2} \, dx=\text {Exception raised: ValueError} \]
[In]
[Out]
none
Time = 0.36 (sec) , antiderivative size = 384, normalized size of antiderivative = 1.51 \[ \int \frac {\cos ^4(c+d x) \cot ^2(c+d x)}{(a+b \sin (c+d x))^2} \, dx=-\frac {\frac {12 \, b \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) \right |}\right )}{a^{3}} - \frac {3 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )}{a^{2}} + \frac {3 \, {\left (6 \, a^{2} - 5 \, b^{2}\right )} {\left (d x + c\right )}}{b^{4}} + \frac {6 \, {\left (b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 4 \, a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 4 \, a\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1\right )}^{2} b^{3}} - \frac {12 \, {\left (3 \, a^{6} - 4 \, a^{4} b^{2} - a^{2} b^{4} + 2 \, b^{6}\right )} {\left (\pi \left \lfloor \frac {d x + c}{2 \, \pi } + \frac {1}{2} \right \rfloor \mathrm {sgn}\left (a\right ) + \arctan \left (\frac {a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + b}{\sqrt {a^{2} - b^{2}}}\right )\right )}}{\sqrt {a^{2} - b^{2}} a^{3} b^{4}} - \frac {4 \, a b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 12 \, a^{4} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 21 \, a^{2} b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 4 \, b^{5} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 12 \, a^{5} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 24 \, a^{3} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 14 \, a b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 3 \, a^{2} b^{3}}{{\left (a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 2 \, b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )} a^{3} b^{3}}}{6 \, d} \]
[In]
[Out]
Time = 13.57 (sec) , antiderivative size = 5214, normalized size of antiderivative = 20.53 \[ \int \frac {\cos ^4(c+d x) \cot ^2(c+d x)}{(a+b \sin (c+d x))^2} \, dx=\text {Too large to display} \]
[In]
[Out]